Thursday, February 28, 2013

Hydrogen Gas

Purpose: To determine the percent yield of hydrogen waste produced in the reaction of magnesium with hydrochloride acid
Materials:
Electronic balance scale
splatter measuring tube
10mL or 25mL graduate cylinder
Retort stand and clamp
chiliad mL graduated cylinder containing about 800mL of water which has been brought to mode temperature
Copper wire
1 hole 00 rubber stopper
2.5 cm gaffe of Mg ribbon steel wool
6 mol of dm3 HCL(aq)
information Table1: Quantitative observations of magnesium reacting with hydrochloride acid
Substances Measurement including uncertainty
Mass of 2.5cm magnesium 0.037g±0.0005
mode temperature19°C±0.5
Volume of 6.00 dm3 HCL(aq) used15.1cm3 ±0.5
Volume of bollixoline collected (water levels are equal to room pressure)36.5cm3 ±0.1
Length of magnesium2.6cm±0.05

Table2: Qualitative observations of the magnesium, reacting in the hydrochloride acid
SubstancesQualitative Observations
2.

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5cm Magnesium (Mg) ribbon break away thin strip hard
Shiny bendable
Hydrochloride acid (HCL)Transparent
bonny like water
The reaction occurred when the hydrochloride acid reaches the magnesium (Mg) ribbon startle to dissolve
Separating the H2 gas from the water
gas bubbles attached to copper wire
by and by the reaction occurred (the period of 5 minutes waiting for the gas in the test tube to come to room temperature)No more air bubbles
No change of colour
Transparent water
Gas bubbles attached to copper coil
Temperature of the water after the reaction19.5°C ±0.5
Pressure101.38kPa

Calculations:

Step 1: Equation
Mg(s) + 2HCL (aq) MgCl2 (aq) + H2 (g)

Step 2: pose the number of moles of Mg
n = m/M
Molar mass of Mg = 24.31g/mol
m = 0.037±0.0005g

n = 0.037±0.0005g ÷ 24.31g/mol
n = 1.52x10-3 ±0.0005mol

Uncertainty Calculations:
0.0005 ÷ 0.037g x coke = 1.4%
0.0005 ÷24.31g/mol x 100 = 0.002%
1.4% + 0.002% = 1.402%
1.402% of 0.037 = 0.0005
Therefore the uncertainty is ±0.0005

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